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MHT CET 2025 (19 Apr, Shift 1) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2025 (19 Apr, Shift 1)

Q12MHT CET 2025 · 19 APR · SHIFT 1Easy

Force on Current-Carrying Conductors

Two long straight wires A and B carrying equal current 'I' were kept parallel to each other at distance ' $d$ ' apart. Magnitude of magnetic force experienced by length $L$ of wire $A$ is ' $F$ '. If the distance between the wires is made half and currents are doubled, force $F_2$ on length $L$ of wire $A$ will be

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Answer: (c)

$F = \dfrac{\mu_0 I^2 L}{2\pi d}$ , so $F \propto \dfrac{I^2}{d}$ .
$\dfrac{F_2}{F} = \dfrac{(2)^2}{1/2} = 8$
So the answer is (c) $8F$ .

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