Physics Circle home Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Force on Current-Carrying Conductors›Question 4

MHT CET 2026 (13 Apr, Shift 2) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2026 (13 Apr, Shift 2)

Q4MHT CET 2026 · 13 APR · SHIFT 2Easy

Force on Current-Carrying Conductors

Two long straight wires are arranged parallel to each other and are kept 2020 cm apart in vacuum. They carry currents of 22 A and 44 A respectively in the same direction. What will be the magnetic force on a length of 1010 cm of either wire?

(μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} SI units)

Show answer and solution

Answer: (d)

  1. F=μ0I1I2L2πdF = \dfrac{\mu_0 I_1 I_2 L}{2\pi d}
  2. F=2×10−7×2×4×0.10.2=8×10−7 NF = \dfrac{2 \times 10^{-7} \times 2 \times 4 \times 0.1}{0.2} = 8 \times 10^{-7}\text{ N}
  3. So the answer is (d) 8×10−7 N8 \times 10^{-7}\text{ N}.
Report a mistake

More questions on Force on Current-Carrying Conductors