Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is 5.0 cm. The magnitude of the magnetic field at a point P midway between the wires is _______ (Given: μ₀ = 4π × 10⁻⁷ TmA⁻¹) Numerical answer type. Work it out, then open the answer.

Answer: 160. Opposite currents: fields at the midpoint add; r = 2.5 cm = 0.025 m. Each: B = (μ₀ I)/(2π r) = 2 × 10⁻⁷ × 100.025 = 8 × 10⁻⁵ T Total = 1.6 × 10⁻⁴ T = 160

Two long, straight wires carry equal currents in opposite directions… | JEE Main 2024 (27 Jan, Shift 1)

Q29JEE Main 2024 · 27 JAN · SHIFT 1Easy

Magnetic Field of Straight Wires

Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is $5.0\text{ cm}$ . The magnitude of the magnetic field at a point $\text{P}$ midway between the wires is _______ $\mu\text{T}$

(Given: $\mu_0 = 4\pi \times 10^{-7}\text{ TmA}^{-1}$ )

Numerical answer type. Work it out, then open the answer.

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Answer: 160

Opposite currents: fields at the midpoint add; $r = 2.5\text{ cm} = 0.025\text{ m}$ .
Each: $B = \frac{\mu_0 I}{2\pi r} = \frac{2 \times 10^{-7} \times 10}{0.025} = 8 \times 10^{-5}\text{ T}$
Total $= 1.6 \times 10^{-4}\text{ T} = 160\ \mu\text{T}$

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