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MHT CET 2024 (3 May, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2024 (3 May, Shift 2)

Q83MHT CET 2024 · 3 MAY · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Two loops ' $A$ ' and ' $B$ ' of radii ' $R_1$ ' and ' $R_2$ ' are made from uniform wire. If moment of inertia of ' A ' is ' $I_A$ ' and that of ' B ' is ' $I_B$ ', then $R_2/R_1$ is $\left[\frac{I_A}{I_B} = 27\right]$

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Answer: (c)

Same wire: $M \propto R$ , so $I \propto R^3$ .
$\left(\frac{R_1}{R_2}\right)^3 = 27 \Rightarrow \frac{R_1}{R_2} = 3$
So the answer is (c) $\frac{R_2}{R_1} = 1 : 3$ .

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