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MHT CET 2026 (12 May, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (12 May, Shift 2)

Q27MHT CET 2026 · 12 MAY · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Two loops $A$ and $B$ of radii $R_1$ and $R_2$ are made from uniform wire. If moment of inertia of loops $A$ and $B$ is $I_A$ and $I_B$ respectively then $\frac{R_1}{R_2}$ is (Given: $\frac{I_A}{I_B} = 27$ )

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Answer: (d)

Same wire: $M = \lambda (2\pi R) \propto R$ , so $I = MR^2 \propto R^3$ .
$\left(\frac{R_1}{R_2}\right)^3 = 27 \Rightarrow \frac{R_1}{R_2} = 3$
So the answer is (d) $3 : 1$ .

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