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MHT CET 2024 (16 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2024 (16 May, Shift 1)

Q79MHT CET 2024 · 16 MAY · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Two loops P and Q of radii R1R_1 and R2R_2 are made from uniform metal wire of same material. IpI_p and IQI_Q be the moment of inertia of loop P and Q respectively then ratio R1/R2R_1/R_2 is (( Given IP/IQ=27)I_P/I_Q = 27)

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Answer: (b)

  1. Same wire: M∝RM \propto R, so I∝R3I \propto R^3.
  2. (R1R2)3=27⇒R1R2=3\left(\frac{R_1}{R_2}\right)^3 = 27 \Rightarrow \frac{R_1}{R_2} = 3
  3. So the answer is (b) 3:13 : 1.
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