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JEE Main 2004 (AIEEE) · Connected Bodies & Pulleys

Connected Bodies & Pulleys question from JEE Main 2004 (AIEEE)

Q43JEE Main 2004 · AIEEEEasy

Connected Bodies & Pulleys

Two masses m1=5 kgm_1 = 5\text{ kg} and m2=4.8 kgm_2 = 4.8\text{ kg} tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when left free to move? (g=9.8 m/s2)\left(g = 9.8\text{ m/s}^{2}\right)

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Answer: (c)

  1. a=(m1−m2)gm1+m2=(5−4.8)×9.89.8a = \dfrac{(m_1 - m_2)g}{m_1 + m_2} = \dfrac{(5 - 4.8) \times 9.8}{9.8}
  2. a=0.2 m/s2a = 0.2\text{ m/s}^2, so the answer is (c).
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