Two massless springs of spring constants K₁ and K₂ are connected one after the other forming a single chain, suspended vertically and a certain mass is attached to the free end. If x₁ and x₂ are their respective extensions and 'F' is their stretching force, the total extension produced is (a) F(K₁+K₂) (b) F(1/K₁ - 1/K₂) (c) F(K₁-K₂) (d) F(1/K₁ + 1/K₂)

Answer: (d). In series each spring carries the same force F: x₁ = F/K₁, x₂ = F/K₂. x = x₁ + x₂ = F(1/K₁ + 1/K₂) So the answer is (d).

Two massless springs of spring constants K₁ and K₂ are connected one… | MHT CET 2026 (11 Apr, Shift 1)

Q19MHT CET 2026 · 11 APR · SHIFT 1Medium

Spring Systems

Two massless springs of spring constants $K_1$ and $K_2$ are connected one after the other forming a single chain, suspended vertically and a certain mass is attached to the free end. If $x_1$ and $x_2$ are their respective extensions and 'F' is their stretching force, the total extension produced is

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Answer: (d)

In series each spring carries the same force $F$ : $x_1 = F/K_1$ , $x_2 = F/K_2$ .
$x = x_1 + x_2 = F\left(\frac{1}{K_1} + \frac{1}{K_2}\right)$
So the answer is (d).

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Spring Systems question from MHT CET 2026 (11 Apr, Shift 1)

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