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JEE Main 2022 (25 Jun, Shift 2) · Dielectrics

Dielectrics question from JEE Main 2022 (25 Jun, Shift 2)

Q62JEE Main 2022 · 25 JUN · SHIFT 2Easy

Dielectrics

Two metallic plates form a parallel plate capacitor. The distance between the plates is 'd'. A metal sheet of thickness d2\frac{d}{2} and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

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Answer: (a)

  1. Metal sheet: C′=ε0Ad−tC' = \frac{\varepsilon_0 A}{d - t}.
  2. d−d2=d2d - \frac{d}{2} = \frac{d}{2}, so C′=2CC' = 2C.
  3. So the ratio is 2:12:1, answer (a).
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