Two moles of helium are mixed with n moles of hydrogen. If (Cp)/(Cv) = 3/2 for the mixture, then the value of n is: (a) 1 (b) 3 (c) 2 (d) 3 / 2

Answer: (c). Total CV = 2(1.5R) + n(2.5R), total CP = 2(2.5R) + n(3.5R). (5 + 3.5n)/(3 + 2.5n) = 3/2 ⇒ 10 + 7n = 9 + 7.5n n = 2 So the answer is (c) 2.

Two moles of helium are mixed with n moles of hydrogen. If (Cp)/(Cv)… | JEE Main 2018 (16 Apr, Shift 1)

Q53JEE Main 2018 · 16 APR · SHIFT 1Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Two moles of helium are mixed with n moles of hydrogen. If $\frac{C_p}{C_v} = \frac{3}{2}$ for the mixture, then the value of n is:

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Answer: (c)

Total $C_V = 2(1.5R) + n(2.5R)$ , total $C_P = 2(2.5R) + n(3.5R)$ .
$\dfrac{5 + 3.5n}{3 + 2.5n} = \dfrac{3}{2} \Rightarrow 10 + 7n = 9 + 7.5n$
$n = 2$
So the answer is (c) 2.

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2018 (16 Apr, Shift 1)

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