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MHT CET 2021 (24 Sep, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from MHT CET 2021 (24 Sep, Shift 2)

Q75MHT CET 2021 · 24 SEP · SHIFT 2Easy

Superposition, Coherence & Intensity

Two monochromatic beams of intensities I and 4 I respectively are superposed to form a steady interference pattern. The maximum and minimum intensities in the pattern are

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Answer: (d)

  1. Imax=(I1+I2)2I_{max} = (\sqrt{I_1}+\sqrt{I_2})^2, Imin=(I1−I2)2I_{min} = (\sqrt{I_1}-\sqrt{I_2})^2
  2. Imax=(I+2I)2=9II_{max} = (\sqrt{I}+2\sqrt{I})^2 = 9I
  3. Imin=(2I−I)2=II_{min} = (2\sqrt{I}-\sqrt{I})^2 = I
  4. So the answer is (d) 9I9I and II.
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