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JEE Main 2023 (1 Feb, Shift 2) · Reflection & Mirrors

Reflection & Mirrors question from JEE Main 2023 (1 Feb, Shift 2)

Q24JEE Main 2023 · 1 FEB · SHIFT 2Medium

Reflection & Mirrors

Two objects A and B are placed at 15 cm and 25 cm from the pole in front of a concave mirror having radius of curvature 40 cm. The distance between images formed by the mirror is _______________.

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Answer: (c)

  1. f=−20 cmf = -20\text{ cm}.
  2. A (u=−15u = -15, inside F): 1v=−120+115=160⇒v=+60 cm\frac{1}{v} = -\frac{1}{20} + \frac{1}{15} = \frac{1}{60} \Rightarrow v = +60\text{ cm} (behind the mirror)
  3. B (u=−25u = -25): 1v=−120+125=−1100⇒v=−100 cm\frac{1}{v} = -\frac{1}{20} + \frac{1}{25} = -\frac{1}{100} \Rightarrow v = -100\text{ cm} (in front)
  4. Distance between images =60+100=160 cm= 60 + 100 = 160\text{ cm}, so the answer is (c).
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