Two objects are projected with same velocity 'u' at different angles α and β with the horizontal. If α + β = 90°, the ratio of horizontal range of the first object to the second object will be [sin (π - θ) = sin θ] (a) 4: 1 (b) 2: 1 (c) 1: 1 (d) 1: 2

Answer: (c). R = (u²sin 2θ)/(g); with β = 90° - α, sin 2β = sin (180° - 2α) = sin 2α. So R₁ = R₂. So the answer is (c) 1: 1.

Two objects are projected with same velocity 'u' at different angles… | MHT CET 2026 (16 Apr, Shift 2)

Q1MHT CET 2026 · 16 APR · SHIFT 2Easy

Comparing Two Projectiles

Two objects are projected with same velocity 'u' at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha + \beta = 90^\circ$ , the ratio of horizontal range of the first object to the second object will be $[\sin(\pi - \theta) = \sin\theta]$

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Answer: (c)

$R = \frac{u^2\sin 2\theta}{g}$ ; with $\beta = 90^\circ - \alpha$ , $\sin 2\beta = \sin(180^\circ - 2\alpha) = \sin 2\alpha$ .
So $R_1 = R_2$ .
So the answer is (c) $1 : 1$ .

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