Two objects are projected with same velocity 'u' however at different angles α and β with the horizontal. If α + β = 90°, the ratio of horizontal range of the first object to the 2nd object will be: (a) 1: 1 (b) 2: 1 (c) 1: 2 (d) 4: 1

Answer: (a). β = 90° - α ⇒ sin 2β = sin (180° - 2α) = sin 2α Same u, so R₁ = R₂. So the answer is (a) 1: 1.

Two objects are projected with same velocity 'u' however at different… | JEE Main 2023 (25 Jan, Shift 2)

Q14JEE Main 2023 · 25 JAN · SHIFT 2Easy

Comparing Two Projectiles

Two objects are projected with same velocity 'u' however at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha + \beta = 90^\circ$ , the ratio of horizontal range of the first object to the 2nd object will be:

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Answer: (a)

$\beta = 90^\circ - \alpha \Rightarrow \sin 2\beta = \sin(180^\circ - 2\alpha) = \sin 2\alpha$
Same $u$ , so $R_1 = R_2$ .
So the answer is (a) $1 : 1$ .

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