Two objects of masses ' m₁ ' and ' m₂ ' are moving in the circles of radii ' r₁ ' and ' r₂ ' respectively. Their respective angular speeds ' ω₁ ' and ' ω₂ ' are such that they both complete one revolution in the same time ' t '. The ratio of linear speed of ' m₂ ' to that of ' m₁ ' is (a) ω₁: ω₂ (b) T₂: T₁ (c) m₁: m₂ (d) r₂: r₁

Answer: (d). Same period ⇒ same angular speed ω. v = rω ⇒ v ∝ r. v₂: v₁ = r₂: r₁. So the answer is (d) r₂: r₁.

Two objects of masses ' m₁ ' and ' m₂ ' are moving in the circles of… | MHT CET 2024 (16 May, Shift 2)

Q17MHT CET 2024 · 16 MAY · SHIFT 2Easy

Angular Variables

Two objects of masses ' $m_1$ ' and ' $m_2$ ' are moving in the circles of radii ' $r_1$ ' and ' $r_2$ ' respectively. Their respective angular speeds ' $\omega_1$ ' and ' $\omega_2$ ' are such that they both complete one revolution in the same time ' $t$ '. The ratio of linear speed of ' $m_2$ ' to that of ' $m_1$ ' is

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Answer: (d)

Same period $\Rightarrow$ same angular speed $\omega$ .
$v = r\omega \Rightarrow v \propto r$ .
$v_2 : v_1 = r_2 : r_1$ .
So the answer is (d) $r_2 : r_1$ .

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Angular Variables question from MHT CET 2024 (16 May, Shift 2)

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