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JEE Main 2022 (25 Jul, Shift 2) · Dielectrics

Dielectrics question from JEE Main 2022 (25 Jul, Shift 2)

Q69JEE Main 2022 · 25 JUL · SHIFT 2Medium

Dielectrics

Two parallel plate capacitors of capacity C and 3C are connected in parallel combination and charged to a potential difference 18 V. The battery is then disconnected and the space between the plates of the capacitor of capacity C is completely filled with a material of dielectric constant 9. The final potential difference across the combination of capacitors will be ___________ V.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

  1. Charge: Q=(C+3C)×18=72CQ = (C + 3C) \times 18 = 72C, constant after disconnection.
  2. New capacitance: 9C+3C=12C9C + 3C = 12C.
  3. V′=72C12C=6 VV' = \frac{72C}{12C} = 6\text{ V}
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