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NEET 1997 (AIPMT) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from NEET 1997 (AIPMT)

Q71NEET 1997 · AIPMTEasy

Force on Current-Carrying Conductors

Two parallel wires in free space are 10 cm10\text{ cm} apart and each carries a current of 10 A10\text{ A} in the same direction. The force exerted by one wire on the other, per metre length is

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Answer: (c)

  1. Fl=μ0I1I22πd=2×10−7×10×100.1\frac{F}{l} = \frac{\mu_0 I_1 I_2}{2\pi d} = \frac{2\times10^{-7}\times10\times10}{0.1}
  2. Fl=2×10−4 N/m\frac{F}{l} = 2\times10^{-4}\text{ N/m}
  3. Same direction currents attract.
  4. So the answer is (c) 2×10−4 N2\times10^{-4}\text{ N}, attractive.
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