Two parallel wires of equal lengths are separated by a distance of 3 m from each other. The currents flowing through 1 st and 2 nd wire is 3 A and 4.5 A respectively in opposite directions. The resultant magnetic field at mid point between the wires (μ₀ = permeability of free space) (a) (μ₀)/(2π) (b) (3μ₀)/(2π) (c) (7μ₀)/(2π) (d) (5μ₀)/(2π)

Answer: (d). Opposite currents: fields at the midpoint add. B = (μ₀ (3 + 4.5))/(2π × 1.5) = (7.5 μ₀)/(3π) = (5μ₀)/(2π) So the answer is (d) (5μ₀)/(2π).

Two parallel wires of equal lengths are separated by a distance of 3… | MHT CET 2023 (11 May, Shift 1)

Q38MHT CET 2023 · 11 MAY · SHIFT 1Easy

Magnetic Field of Straight Wires

Two parallel wires of equal lengths are separated by a distance of $3\text{ m}$ from each other. The currents flowing through $1$ st and $2$ nd wire is $3\text{ A}$ and 4.5 A respectively in opposite directions. The resultant magnetic field at mid point between the wires $(\mu_0 =$ permeability of free space)

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Answer: (d)

Opposite currents: fields at the midpoint add.
$B = \frac{\mu_0 (3 + 4.5)}{2\pi \times 1.5} = \frac{7.5\,\mu_0}{3\pi} = \frac{5\mu_0}{2\pi}$
So the answer is (d) $\frac{5\mu_0}{2\pi}$ .

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