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MHT CET 2026 (12 May, Shift 2) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2026 (12 May, Shift 2)

Q4MHT CET 2026 · 12 MAY · SHIFT 2Easy

Magnetic Field of Straight Wires

Two parallel wires of equal lengths are separated by a distance of $3$ m from each other. The currents flowing through first and second wire is $3$ A and $4.5$ A respectively in opposite directions. The resultant magnetic field at mid point of both the wires is ( $\mu_0$ = permeability of free space)

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Answer: (a)

For opposite currents, the fields at the midpoint are in the same direction and add.
Midpoint distance $r = 1.5\text{ m}$ : $B = \frac{\mu_0}{2\pi r}(I_1 + I_2) = \frac{\mu_0 (3 + 4.5)}{2\pi \times 1.5}$
$B = \frac{7.5\,\mu_0}{3\pi} = \frac{5\mu_0}{2\pi}$
So the answer is (a) $\frac{5\mu_0}{2\pi}$ .

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