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MHT CET 2026 (12 May, Shift 1) · Angular Variables

Angular Variables question from MHT CET 2026 (12 May, Shift 1)

Q11MHT CET 2026 · 12 MAY · SHIFT 1Medium

Angular Variables

Two particles A and B are moving in uniform circular motion in concentric circles of radii rAr_A and rBr_B with speeds vAv_A and vBv_B respectively. TAT_A and TBT_B are the time periods of rotation of the particles respectively and their relation is TA=3TBT_A = 3T_B. The ratio of angular speed of B to that of A will be

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Answer: (d)

  1. ω=2π/T⇒ω∝1/T\omega = 2\pi/T \Rightarrow \omega \propto 1/T.
  2. ωBωA=TATB=3\frac{\omega_B}{\omega_A} = \frac{T_A}{T_B} = 3.
  3. So the answer is (d) 3:13:1.
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