Two particles A and B of masses m₁ and m₂ ( m₁ > m₂) have the same de-Broglie wavelength, then (a) their momenta are the same (b) their energies are the same (c) momenta of A is less than the momenta of B (d) energy of A is more than energy of B

Answer: (a). λ = h/p, so equal λ means equal momentum p, whatever the masses. Energy E = p²/2m then differs: the heavier A has less energy. So the answer is (a) their momenta are the same.

Two particles A and B of masses m₁ and m₂ ( m₁ > m₂) have the same… | MHT CET 2026 (14 May, Shift 1)

Q1MHT CET 2026 · 14 MAY · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

Two particles A and B of masses $m_1$ and $m_2$ ( $m_1 > m_2$ ) have the same de-Broglie wavelength, then

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Answer: (a)

$\lambda = \dfrac{h}{p}$ , so equal $\lambda$ means equal momentum $p$ , whatever the masses.
Energy $E = \dfrac{p^2}{2m}$ then differs: the heavier A has less energy.
So the answer is (a) their momenta are the same.

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Matter Waves: de Broglie Wavelength question from MHT CET 2026 (14 May, Shift 1)

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