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JEE Main 2019 (12 Jan, Shift 2) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2019 (12 Jan, Shift 2)

Q63JEE Main 2019 · 12 JAN · SHIFT 2Difficult

Angular Momentum & its Conservation

Two particles A, B are moving on two concentric circles of radii R1 and R2 with equal angular speed ω\omega. At t = 0, their positions and direction of motion are shown in the figure.:

Figure

The relative velocity V⃗A−V⃗B\vec{V}_A - \vec{V}_B at t = π2ω\frac{\pi}{2\omega} is given by:

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Answer: (b)

xyAωR₁BωR₂t = π/2ω
  1. A moves anticlockwise, B moves clockwise; in time t=π2ωt = \frac{\pi}{2\omega} each turns through 90∘90^\circ.
  2. A reaches (0,R1)(0, R_1); anticlockwise motion there is along −i^-\hat{i}: V⃗A=−ωR1i^\vec{V}_A = -\omega R_1\hat{i}.
  3. B reaches (0,−R2)(0, -R_2); clockwise motion there is also along −i^-\hat{i}: V⃗B=−ωR2i^\vec{V}_B = -\omega R_2\hat{i}.
  4. V⃗A−V⃗B=ω(R2−R1)i^\vec{V}_A - \vec{V}_B = \omega(R_2 - R_1)\hat{i}
  5. So the answer is (b) ω(R2−R1)i^\omega(R_2-R_1)\hat{i}.
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