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JEE Main 2023 (29 Jan, Shift 1) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2023 (29 Jan, Shift 1)

Q38JEE Main 2023 · 29 JAN · SHIFT 1Medium

Satellites - Orbital Velocity & Period

Two particles of equal mass 'mm' move in a circle of radius 'rr' under the action of their mutual gravitational attraction. The speed of each particle will be:

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Answer: (a)

  1. Separation is the diameter 2r2r: Gm2(2r)2=mv2r\frac{Gm^2}{(2r)^2} = \frac{mv^2}{r}
  2. v2=Gm4rv^2 = \frac{Gm}{4r}
  3. So the answer is (a) Gm4r\sqrt{\frac{Gm}{4r}}.
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