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MHT CET 2026 (19 Apr, Shift 2) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from MHT CET 2026 (19 Apr, Shift 2)

Q1MHT CET 2026 · 19 APR · SHIFT 2Easy

Centre of Mass of Discrete Particles

Two particles of masses 22 g and 44 g are situated at the opposite ends, A and B of a wooden bar respectively. Let l(AB)=9l(AB) = 9 cm. The center of mass of the system will be

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Answer: (d)

  1. Take A as origin: xcm=mA⋅0+mB⋅9mA+mBx_{cm} = \frac{m_A \cdot 0 + m_B \cdot 9}{m_A + m_B}
  2. xcm=4×92+4=6x_{cm} = \frac{4 \times 9}{2 + 4} = 6 cm
  3. So the answer is (d) 66 cm from A.
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