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JEE Main 2024 (29 Jan, Shift 2) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from JEE Main 2024 (29 Jan, Shift 2)

Q38JEE Main 2024 · 29 JAN · SHIFT 2Medium

Moving Charge in a Magnetic Field

Two particles $X$ and $Y$ having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describe circular paths of radii $R_1$ and $R_2$ respectively. The mass ratio of $X$ and $Y$ is:

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Answer: (d)

After acceleration $K = qV$ , so $r = \dfrac{\sqrt{2mqV}}{qB}$ .
Equal $q$ , $V$ , $B$ : $r \propto \sqrt{m} \Rightarrow \dfrac{m_X}{m_Y} = \left(\dfrac{R_1}{R_2}\right)^2$
So the answer is (d) $\left(\frac{R_1}{R_2}\right)^2$ .

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