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MHT CET 2026 (19 May, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from MHT CET 2026 (19 May, Shift 1)

Q9MHT CET 2026 · 19 MAY · SHIFT 1Medium

Moving Charge in a Magnetic Field

Two particles X and Y of masses 'm1m_1' and 'm2m_2' respectively, having equal charges after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular paths of radii 'r1r_1 ' and 'r2r_2' respectively. The ratio of 'r1r_1' and 'r2r_2' is

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Answer: (c)

  1. After acceleration: 12mv2=qV⇒mv=2mqV\tfrac{1}{2}mv^2 = qV \Rightarrow mv = \sqrt{2mqV}
  2. r=mvqB=2mqVqB⇒r∝mr = \dfrac{mv}{qB} = \dfrac{\sqrt{2mqV}}{qB} \Rightarrow r\propto\sqrt{m} for equal qq, VV, BB
  3. r1r2=m1m2\dfrac{r_1}{r_2} = \sqrt{\dfrac{m_1}{m_2}}
  4. So the answer is (c).
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