Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Simple Pendulum›Question 73

MHT CET 2019 (2 May, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2019 (2 May, Shift 2)

Q73MHT CET 2019 · 2 MAY · SHIFT 2Medium

Simple Pendulum

Two pendulums begin to swing simultaneously. The first pendulum makes nine full oscillations when the other makes seven. The ratio of the lengths of the two pendulums is

Show answer and solution

Answer: (a)

  1. Same time: 9T1=7T2⇒T1T2=799T_1 = 7T_2 \Rightarrow \frac{T_1}{T_2} = \frac{7}{9}.
  2. l∝T2⇒l1l2=4981l \propto T^2 \Rightarrow \frac{l_1}{l_2} = \frac{49}{81}
  3. So the answer is (a) 4981\frac{49}{81}.
Report a mistake

More questions on Simple Pendulum