Two persons pull a wire towards themselves. Each person exerts a force of 200 N on the wire. Young's modulus of the material of wire is 1 × 10¹¹ N m⁻². Original length of the wire is 2 m and the area of cross section is 2 cm². The wire will extend in length by _________. Numerical answer type. Work it out, then open the answer.

Answer: 20. Both ends pulled with 200 N, so the tension in the wire is T = 200 N (not 400 N). Δ l = TL/AY = 200 × 22 × 10⁻⁴ × 10¹¹ = 4002 × 10⁷ Δ l = 2 × 10⁻⁵ m = 20

Two persons pull a wire towards themselves. Each person exerts a… | JEE Main 2024 (9 Apr, Shift 1)

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Wire Combinations & Special Cases

Two persons pull a wire towards themselves. Each person exerts a force of $200\text{ N}$ on the wire. Young's modulus of the material of wire is $1 \times 10^{11}\text{ N m}^{-2}$ . Original length of the wire is $2\text{ m}$ and the area of cross section is $2\text{ cm}^2$ . The wire will extend in length by _________ $\mu\text{m}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 20

Both ends pulled with 200 N, so the tension in the wire is $T = 200\text{ N}$ (not 400 N).
$\Delta l = \frac{TL}{AY} = \frac{200 \times 2}{2 \times 10^{-4} \times 10^{11}} = \frac{400}{2 \times 10^{7}}$
$\Delta l = 2 \times 10^{-5}\text{ m} = 20\ \mu\text{m}$

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