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Electric Charge & Coulomb's Law question from NEET 2013

Q70NEET 2013Medium

Electric Charge & Coulomb's Law

Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now becomes

Figure

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Answer: (d)

  1. For each ball tan⁡θ=Fmg\tan\theta = \dfrac{F}{mg} and from the geometry tan⁡θ=r/2y\tan\theta = \dfrac{r/2}{y}.
  2. kq2r2mg=r2y⇒r3=2kq2ymg∝y\dfrac{kq^2}{r^2 mg} = \dfrac{r}{2y} \Rightarrow r^3 = \dfrac{2kq^2y}{mg} \propto y
  3. Height becomes y/2y/2: r′3=r32⇒r′=r23r'^3 = \dfrac{r^3}{2} \Rightarrow r' = \dfrac{r}{\sqrt[3]{2}}
  4. So the answer is (d).
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