Two plane polarised light waves combine at a certain point whose electric field components are E₁ = E₀ sin ω t and E₂ = E₀ sin (ω t + π/3). The amplitude of the resultant wave is ( cos 60° = 0.5) (a) 3E₀ (b) √(3)E₀ (c) E₀ (d) E₀/√(3)

Answer: (b). Same direction of vibration, phase difference φ = π/3: A = √(E₀² + E₀² + 2E₀²cos φ). A = √(2E₀² + 2E₀²(0.5)) = √(3)E₀ So the answer is (b) √(3)E₀.

Two plane polarised light waves combine at a certain point whose… | MHT CET 2026 (12 May, Shift 2)

Q12MHT CET 2026 · 12 MAY · SHIFT 2Medium

Polarisation

Two plane polarised light waves combine at a certain point whose electric field components are $E_1 = E_0 \sin \omega t$ and $E_2 = E_0 \sin(\omega t + \pi/3)$ . The amplitude of the resultant wave is ( $\cos 60^\circ = 0.5$ )

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Answer: (b)

Same direction of vibration, phase difference $\phi = \pi/3$ : $A = \sqrt{E_0^2 + E_0^2 + 2E_0^2\cos\phi}$ .
$A = \sqrt{2E_0^2 + 2E_0^2(0.5)} = \sqrt{3}E_0$
So the answer is (b) $\sqrt{3}E_0$ .

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Polarisation question from MHT CET 2026 (12 May, Shift 2)

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