Two plane polarized light waves combine at a certain point whose electric field components are E₁ = E₀ sin ω t E₂ = E₀ sin (ω t + π/3) Find the amplitude of the resultant wave. (a) 1.7 E₀ (b) E₀ (c) 0.9 E₀ (d) 3.4 E₀

Answer: (a). Phase difference φ = π/3: A = √(E₀² + E₀² + 2E₀²cos 60°). A = √(3)E₀ ≈ 1.73E₀ So the answer is (a) 1.7 E₀.

Two plane polarized light waves combine at a certain point whose… | JEE Main 2025 (7 Apr, Shift 1)

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Polarisation

Two plane polarized light waves combine at a certain point whose electric field components are $E_1 = E_0 \sin \omega t$

$E_2 = E_0 \sin\left(\omega t + \frac{\pi}{3}\right)$

Find the amplitude of the resultant wave.

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Answer: (a)

Phase difference $\phi = \pi/3$ : $A = \sqrt{E_0^2 + E_0^2 + 2E_0^2\cos 60^\circ}$ .
$A = \sqrt{3}E_0 \approx 1.73E_0$
So the answer is (a) $1.7\,E_0$ .