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MHT CET 2025 (25 Apr, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2025 (25 Apr, Shift 1)

Q14MHT CET 2025 · 25 APR · SHIFT 1Easy

Acceleration Due to Gravity

Two planets A and B have densities ' $\rho_1$ ', ' $\rho_2$ ' and have radii ' $r_1$ ', ' $r_2$ ', respectively. The ratio of acceleration due to gravity on $A$ to that of $B$ is

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Answer: (b)

$g = \frac{4}{3}\pi G\rho r$ , so $g \propto \rho r$ .
$g_A : g_B = r_1\rho_1 : r_2\rho_2$
So the answer is (b).

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