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JEE Main 2023 (13 Apr, Shift 2) · Heat Conduction

Heat Conduction question from JEE Main 2023 (13 Apr, Shift 2)

Q26JEE Main 2023 · 13 APR · SHIFT 2Medium

Heat Conduction

Two plates A\text{A} and B\text{B} have thermal conductivities 84 W m−1 K−184\text{ W m}^{-1}\text{ K}^{-1} and 126 W m−1 K−1126\text{ W m}^{-1}\text{ K}^{-1} respectively. They have same surface area and same thickness. They are placed in contact along their surfaces. If the temperatures of the outer surfaces of A\text{A} and B\text{B} are kept at 100∘C100^\circ\text{C} and 0∘C0^\circ\text{C} respectively, then the temperature of the surface of contact in steady state is _____________ ∘C^\circ\text{C}.

Numerical answer type. Work it out, then open the answer.

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Answer: 40

  1. Same area and thickness: R∝1KR \propto \dfrac{1}{K}, so RARB=12684=32\dfrac{R_A}{R_B} = \dfrac{126}{84} = \dfrac{3}{2}
  2. Drop across A =100×35=60∘= 100\times\dfrac{3}{5} = 60^\circC
  3. Contact temperature =100−60=40∘= 100 - 60 = 40^\circC
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