Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Field & Field Lines›Question 17

MHT CET 2024 (10 May, Shift 1) · Electric Field & Field Lines

Electric Field & Field Lines question from MHT CET 2024 (10 May, Shift 1)

Q17MHT CET 2024 · 10 MAY · SHIFT 1Medium

Electric Field & Field Lines

Two point charges +10 q and -4 q are located at x=0x = 0 and x=Lx = L respectively. What is the location of a point on the xx-axis from the origin, which the net electric field due to these two point charges is zero?( r=r = required distance))

Show answer and solution

Answer: (a)

  1. The null point lies beyond the smaller charge −4q-4q at B, at distance rr to its right.
  2. 10q(L+r)2=4qr2⇒rL+r=25\dfrac{10q}{(L+r)^2} = \dfrac{4q}{r^2} \Rightarrow \dfrac{r}{L+r} = \dfrac{\sqrt{2}}{\sqrt{5}}
  3. r5=2L+2r⇒r=2 L5−2r\sqrt{5} = \sqrt{2}L + \sqrt{2}r \Rightarrow r = \dfrac{\sqrt{2}\,L}{\sqrt{5} - \sqrt{2}}, right of B
  4. So the answer is (a).
Report a mistake

More questions on Electric Field & Field Lines