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JEE Main 2026 (2 Apr, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2026 (2 Apr, Shift 2)

Q6JEE Main 2026 · 2 APR · SHIFT 2Easy

Electric Flux & Gauss's Law

Two point charges $8\ \mu\text{C}$ and $-2\ \mu\text{C}$ are located at $x = 2$ cm and $x = 4$ cm, respectively on the $x$ -axis. The ratio of electric flux due to these charges through two spheres of radii 3 cm and 5 cm with their centers at the origin is ________.

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Answer: (c)

Sphere of radius 3 cm encloses only $8\ \mu$ C (at 2 cm): $\phi_1 = \dfrac{8\ \mu\text{C}}{\varepsilon_0}$ .
Sphere of radius 5 cm encloses both: $\phi_2 = \dfrac{(8-2)\ \mu\text{C}}{\varepsilon_0} = \dfrac{6\ \mu\text{C}}{\varepsilon_0}$ .
$\phi_1 : \phi_2 = 8 : 6 = 4 : 3$
So the answer is (c) 4 : 3.

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