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MHT CET 2024 (15 May, Shift 1) · Electric Field & Field Lines

Electric Field & Field Lines question from MHT CET 2024 (15 May, Shift 1)

Q16MHT CET 2024 · 15 MAY · SHIFT 1Medium

Electric Field & Field Lines

Two point charges $+8q$ and $-2q$ are located at $X = 0$ (origin) and $X = L$ respectively. The net electric field due to these two charges is zero at point $P$ on $X$ -axis. The location of point $P$ from the origin is

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Answer: (b)

The null point lies beyond the smaller charge $-2q$ (at $x > L$ ).
$\dfrac{8q}{x^2} = \dfrac{2q}{(x-L)^2} \Rightarrow x - L = \dfrac{x}{2}$
$x = 2L$
So the answer is (b) $2L$ .

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