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MHT CET 2024 (16 May, Shift 1) · Electric Field & Field Lines

Electric Field & Field Lines question from MHT CET 2024 (16 May, Shift 1)

Q15MHT CET 2024 · 16 MAY · SHIFT 1Medium

Electric Field & Field Lines

Two point charges $+8q$ and $-2q$ are located at $x = 0$ and $x = L$ respectively. The location of a point on the $x$ -axis from the origin, at which the net electric field due to these two point charges is zero is

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Answer: (d)

For unlike charges the null point lies outside, nearer the smaller charge, i.e. beyond $x = L$ .
$\dfrac{k(8q)}{x^2} = \dfrac{k(2q)}{(x-L)^2} \Rightarrow \dfrac{x-L}{x} = \dfrac{1}{2}$
$x = 2L$
So the answer is (d) $2L$ .

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