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NEET 2019 · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from NEET 2019

Q65NEET 2019Medium

Electric Charge & Coulomb's Law

Two point charges A and B, having charges +Q and – Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes:

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Answer: (c)

$F = \dfrac{kQ^2}{r^2}$ . 25% of A's charge is $Q/4$ .
After transfer: $A = \dfrac{3Q}{4}$ , $B = -Q + \dfrac{Q}{4} = -\dfrac{3Q}{4}$ .
$F' = \dfrac{k(3Q/4)^2}{r^2} = \dfrac{9}{16}F$
So the answer is (c) $\dfrac{9F}{16}$ .

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