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MHT CET 2026 (20 Apr, Shift 1) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2026 (20 Apr, Shift 1)

Q3MHT CET 2026 · 20 APR · SHIFT 1Easy

Electric Charge & Coulomb's Law

Two point charges $q_1$ and $q_2$ are ' $l$ ' distance apart. If one of the charges is doubled and the distance between them is halved. The magnitude of the force becomes 'n' times, where 'n' is

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Answer: (c)

$F \propto \dfrac{q_1q_2}{l^2}$ .
$F' \propto \dfrac{2q_1q_2}{(l/2)^2} = \dfrac{8q_1q_2}{l^2} = 8F$
So the answer is (c) $n = 8$ .

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