Two point charges ' q₁ ' and ' q₂ ' are separated by a distance ' d '. What is the increase in potential energy of the system when ' q₂ ' is moved towards ' q₁ ' by a distance ' x '? (x < d) ((1)/(4πε₀) = K, constant) (a) -(Kq₁q₂x)/(d(d-x)) (b) -(Kq₁q₂)/(d(d-x)) (c) (Kq₁q₂x)/((d²-x²)) (d) (Kq₁q₂x)/((d²-x²))

Answer: (b). Δ U = Kq₁q₂((1)/(d - x) - 1/d) Δ U = (Kq₁q₂ x)/(d(d - x)) None of the options matches exactly; (a) has the right form but the wrong sign.

Two point charges ' q₁ ' and ' q₂ ' are separated by a distance ' d… | MHT CET 2023 (12 May, Shift 2)

Q38MHT CET 2023 · 12 MAY · SHIFT 2Medium

Electrostatic Potential Energy

Two point charges ' $q_1$ ' and ' $q_2$ ' are separated by a distance ' $d$ '. What is the increase in potential energy of the system when ' $q_2$ ' is moved towards ' $q_1$ ' by a distance ' $x$ '? $(x < d)\ (\frac{1}{4\pi\varepsilon_0} = K$ , constant)

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Answer: (b)

$\Delta U = Kq_1q_2\left(\dfrac{1}{d - x} - \dfrac{1}{d}\right)$
$\Delta U = \dfrac{Kq_1q_2\,x}{d(d - x)}$
None of the options matches exactly; (a) has the right form but the wrong sign.

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Electrostatic Potential Energy question from MHT CET 2023 (12 May, Shift 2)

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