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NEET 2008 (AIPMT) · Progressive Wave Equation

Progressive Wave Equation question from NEET 2008 (AIPMT)

Q96NEET 2008 · AIPMTEasy

Progressive Wave Equation

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?

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Answer: (d)

  1. λ=vT=300×0.05=15\lambda = vT = 300 \times 0.05 = 15 m
  2. Path difference Δx=15−10=5\Delta x = 15 - 10 = 5 m
  3. Δϕ=2πλΔx=2π×515=2π3\Delta\phi = \frac{2\pi}{\lambda}\Delta x = \frac{2\pi \times 5}{15} = \frac{2\pi}{3}
  4. So the answer is (d) 2π/32\pi/3.
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