Two points on a travelling wave having frequency 500 Hz and velocity 300 m/s are 60° out of phase, then the minimum distance between the two points is (a) 0.2 m (b) 0.1 m (c) 0.5 m (d) 0.4 m

Answer: (b). λ = v/f = (300)/(500) = 0.6 m 60° = π/3, so Δ x = (λ)/(2π) × π/3 = (λ)/(6) Δ x = 0.6/6 = 0.1 m So the answer is (b) 0.1 m.

Two points on a travelling wave having frequency 500 Hz and velocity… | MHT CET 2026 (13 May, Shift 1)

Q13MHT CET 2026 · 13 MAY · SHIFT 1Easy

Progressive Wave Equation

Two points on a travelling wave having frequency $500$ Hz and velocity $300$ m/s are $60^\circ$ out of phase, then the minimum distance between the two points is

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Answer: (b)

$\lambda = \frac{v}{f} = \frac{300}{500} = 0.6$ m
$60^\circ = \frac{\pi}{3}$ , so $\Delta x = \frac{\lambda}{2\pi} \times \frac{\pi}{3} = \frac{\lambda}{6}$
$\Delta x = \frac{0.6}{6} = 0.1$ m
So the answer is (b) $0.1$ m.

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