Two points separated by 6 cm on a string has phase difference of 60°. If frequency of oscillation is 500 Hz, the velocity of the wave in m/s is (a) 200 (b) 180 (c) 100 (d) 80

Answer: (b). Δφ = (2π)/(λ)Δ x; 60° = π/3 means Δ x = (λ)/(6). λ = 6 × 6 = 36 cm = 0.36 m v = fλ = 500 × 0.36 = 180 m/s So the answer is (b) 180.

Two points separated by 6 cm on a string has phase difference of 60°… | MHT CET 2026 (15 May, Shift 2)

Q11MHT CET 2026 · 15 MAY · SHIFT 2Easy

Progressive Wave Equation

Two points separated by $6$ cm on a string has phase difference of $60^\circ$ . If frequency of oscillation is $500$ Hz, the velocity of the wave in $\frac{m}{s}$ is

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Answer: (b)

$\Delta\phi = \frac{2\pi}{\lambda}\Delta x$ ; $60^\circ = \frac{\pi}{3}$ means $\Delta x = \frac{\lambda}{6}$ .
$\lambda = 6 \times 6 = 36$ cm $= 0.36$ m
$v = f\lambda = 500 \times 0.36 = 180$ m/s
So the answer is (b) $180$ .

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