Two poloroids P₁ and P₂ are placed parallel to each other with common axis.The light of intensity I₀ passes through a polaroid sheet P₁ and then passes through polaroid P₂. If P₂ is now rotated by 60°, then the intensity of the output light from P₂ will be: (a) I₀/2 (b) I₀/4 (c) Zero (d) I₀/8

Answer: (d). Unpolarised I₀ through P₁: I₁ = I₀/2. P₂ at 60°: I₂ = I₀/2cos ² 60° = I₀/2×1/4 I₂ = I₀/8 So the answer is (d) I₀/8.

Two poloroids P₁ and P₂ are placed parallel to each other with common… | JEE Main 2022 (30 Jul, Shift 2)

Q42JEE Main 2022 · 30 JUL · SHIFT 2Easy

Polarisation

Two poloroids $P_1$ and $P_2$ are placed parallel to each other with common axis.The light of intensity $I_0$ passes through a polaroid sheet $P_1$ and then passes through polaroid $P_2$ . If $P_2$ is now rotated by $60^\circ$ , then the intensity of the output light from $P_2$ will be:

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Answer: (d)

Unpolarised $I_0$ through $P_1$ : $I_1 = \dfrac{I_0}{2}$ .
$P_2$ at $60^\circ$ : $I_2 = \dfrac{I_0}{2}\cos^2 60^\circ = \dfrac{I_0}{2}\times\dfrac{1}{4}$
$I_2 = \dfrac{I_0}{8}$
So the answer is (d) $\dfrac{I_0}{8}$ .

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Polarisation question from JEE Main 2022 (30 Jul, Shift 2)

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