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NEET 2010 (AIPMT, Prelims) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from NEET 2010 (AIPMT, Prelims)

Q74NEET 2010 · AIPMT · PRELIMSEasy

Electric Charge & Coulomb's Law

Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge on an electron)

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Answer: (c)

  1. Charge on each ion q=neq = ne.
  2. F=14πε0n2e2d2⇒n=4πε0Fd2e2F = \dfrac{1}{4\pi\varepsilon_0}\dfrac{n^2e^2}{d^2} \Rightarrow n = \sqrt{\dfrac{4\pi\varepsilon_0 F d^2}{e^2}}
  3. So the answer is (c).
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