Two progressive waves are travelling towards each other with velocity 50 m/s and frequency 200 Hz. The distance between the two consecutive antinodes is (a) 0.125 m (b) 0.150 m (c) 0.175 m (d) 0.200 m

Answer: (a). λ = v/n = 50/200 = 0.25 m. Consecutive antinodes are (λ)/(2) = 0.125 m apart. So the answer is (a) 0.125 m.

Two progressive waves are travelling towards each other with velocity… | MHT CET 2023 (11 May, Shift 2)

Q56MHT CET 2023 · 11 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

Two progressive waves are travelling towards each other with velocity $50\text{ m/s}$ and frequency $200\text{ Hz}$ . The distance between the two consecutive antinodes is

Show answer and solution

Answer: (a)

$\lambda = \frac{v}{n} = \frac{50}{200} = 0.25\text{ m}$ .
Consecutive antinodes are $\frac{\lambda}{2} = 0.125\text{ m}$ apart.
So the answer is (a) $0.125\text{ m}$ .

Report a mistake

More questions on Stationary Waves & Vibrating Strings

A string fixed at both the ends forms standing wave with node separation of 5 cm. If the…MHT CET 2023 (11 May, Shift 1)
In case of a stationary wave pattern which of the following statements is CORRECT?MHT CET 2023 (10 May, Shift 1)
Stationary waves can be produced inMHT CET 2023 (9 May, Shift 2)
A guitar string of length 90 cm vibrates with a fundamental frequency of 120 Hz. The…JEE Main 2023 (8 Apr, Shift 2)
When a string of length ' l ' is divided into three segments of length l₁, l₂ and l₃. The…MHT CET 2023 (9 May, Shift 1)
Sound waves of frequency 600 Hz fall normally on a perfectly reflecting wall. The…MHT CET 2023 (14 May, Shift 2)
A string is stretched between two rigid supports separated by 75 cm. There are no…MHT CET 2023 (14 May, Shift 1)
The fundamental frequency of vibration of a string stretched between two rigid supports…JEE Main 2023 (15 Apr, Shift 1)

Stationary Waves & Vibrating Strings question from MHT CET 2023 (11 May, Shift 2)

More questions on Stationary Waves & Vibrating Strings