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JEE Main 2023 (10 Apr, Shift 2) · Comparing Two Projectiles

Comparing Two Projectiles question from JEE Main 2023 (10 Apr, Shift 2)

Q12JEE Main 2023 · 10 APR · SHIFT 2Easy

Comparing Two Projectiles

Two projectiles are projected at 30∘30^\circ and 60∘60^\circ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

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Answer: (c)

  1. H=u2sin⁡2θ2gH = \frac{u^2\sin^2\theta}{2g}, so H∝sin⁡2θH \propto \sin^2\theta for the same speed.
  2. H1H2=sin⁡230∘sin⁡260∘=1/43/4=13\frac{H_1}{H_2} = \frac{\sin^2 30^\circ}{\sin^2 60^\circ} = \frac{1/4}{3/4} = \frac{1}{3}
  3. So the answer is (c) 1:31 : 3.
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