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JEE Main 2022 (30 Jul, Shift 2) · Comparing Two Projectiles

Comparing Two Projectiles question from JEE Main 2022 (30 Jul, Shift 2)

Q21JEE Main 2022 · 30 JUL · SHIFT 2Medium

Comparing Two Projectiles

Two projectiles are thrown towards each other at 15∘15^\circ and 45∘45^\circ angles respectively with the horizontal at the same speed. The difference between the horizontal distances traveled by the two projectiles is 80 m80\text{ m}. The initial speed of the projectiles is ______ m s−1\text{m s}^{-1}

[Given g=10 m s−2g = 10\text{ m s}^{-2} ]

Numerical answer type. Work it out, then open the answer.

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Answer: 40

  1. R45−R15=u2g(sin⁡90∘−sin⁡30∘)=u22gR_{45} - R_{15} = \frac{u^2}{g}(\sin 90^\circ - \sin 30^\circ) = \frac{u^2}{2g}
  2. u22×10=80⇒u2=1600\frac{u^2}{2\times 10} = 80 \Rightarrow u^2 = 1600
  3. u=40 m s−1u = 40\text{ m s}^{-1}
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