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MHT CET 2024 (11 May, Shift 2) · Terminal Velocity

Terminal Velocity question from MHT CET 2024 (11 May, Shift 2)

Q23MHT CET 2024 · 11 MAY · SHIFT 2Easy

Terminal Velocity

Two rain drops of same radius are falling through air each with a steady speed of 5 cm/s5\text{ cm/s}. If the drops coalesce, the new steady velocity of big drop will be

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Answer: (d)

  1. v∝r2v \propto r^2 and R=n1/3rR = n^{1/3}r, so v′=n2/3vv' = n^{2/3}v.
  2. n=2n = 2: v′=22/3×5=5×(4)1/3v' = 2^{2/3} \times 5 = 5 \times (4)^{1/3} cm/s
  3. So the answer is (d) 5×(4)1/35 \times (4)^{1/3} cm/s.
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