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JEE Main 2026 (2 Apr, Shift 2) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from JEE Main 2026 (2 Apr, Shift 2)

Q5JEE Main 2026 · 2 APR · SHIFT 2Medium

Electrical Power & Heating Effect

Two resistors of 200 $\Omega$ and 400 $\Omega$ are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 $\Omega$ resistance. The potential drop across the bulb is ________ V.

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Answer: (b)

Bulb: $R_b = \dfrac{200^2}{100} = 400\ \Omega$ .
$400 \parallel 400 = 200\ \Omega$ ; total $200 + 200 = 400\ \Omega$ .
$I = 100/400 = 0.25\text{ A}$ , so $V_{bulb} = 0.25 \times 200 = 50\text{ V}$ .
So the answer is (b) 50.

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